Carboxylic Acids and their Derivatives 2 Question 49
49. How will you bring about the following conversion?
“Ethanoic acid to a mixture of methanoic acid and diphenyl ketone.”
$(1990,2 \mathrm{M})$
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Solution:
- $\mathrm{CH}{3}-\mathrm{COOH} \xrightarrow{\mathrm{PCl}{5}} \mathrm{CH}{3} \mathrm{COCl} \xrightarrow[\mathrm{AlCl}{3}]{\mathrm{C}{6} \mathrm{H}{6}} \mathrm{C}{6} \mathrm{H}{5}-\stackrel{|}{\mathrm{O}}-\mathrm{CH}_{3}$
$\xrightarrow{\mathrm{O}{3} / \mathrm{H}{2} \mathrm{O}{2}} \mathrm{C}{6} \mathrm{H}{5}-\stackrel{\mathrm{O}}{\mathrm{C}}-\mathrm{C}{6} \mathrm{H}_{5}+\mathrm{H}-\mathrm{COOH}$
