Carboxylic Acids and their Derivatives 2 Question 13
13. The product of acid hydrolysis of $P$ and $Q$ can be distinguished by
(2003, S, 1M)
(a) Lucas reagent
(b) 2, 4-DNP
(c) Fehling’s solution
(d) $\mathrm{NaHSO}_{3}$
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Answer:
Correct Answer: 13. (c)
Solution:
- $P \xrightarrow[\mathrm{H}{2} \mathrm{O}]{\stackrel{\mathrm{H}^{+}}{\longrightarrow}} \mathrm{CH}{3}-\stackrel{\mathrm{O}}{\mathrm{C}}=\mathrm{CH}{2} \rightleftharpoons \mathrm{CH}{3}-\stackrel{\mathrm{O}}{\mathrm{C}}-\mathrm{CH}{3}$ $\stackrel{\mathrm{I}{2}}{\stackrel{\mathrm{NaOH}}{\longrightarrow} \underset{\mathrm{H}{2} \mathrm{O}}{\mathrm{CHI}{3} \downarrow}} \mathrm{CH}{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{OH} \rightleftharpoons \mathrm{CH}{3} \mathrm{CH}_{2} \mathrm{OH}$
$$ \xrightarrow{\text { Fehling solution }} \underset{\text { Red }}{\mathrm{Cu}_{2} \mathrm{O} \downarrow} $$
