Carboxylic Acids and their Derivatives 1 Question 12
13. The desired product $X$ can be prepared by reacting the major product of the reactions in List-I with one or more appropriate reagents in List-II.
(given, order of migratory aptitude : aryl $>$ alkyl $>$ hydrogen)
$X$
(2018 Adv.)
Q.
The correct option is
(a) $\mathrm{P} \rightarrow 1$; $\mathrm{Q} \rightarrow 2,3 ; \mathrm{R} \rightarrow 1,4 ; \mathrm{S} \rightarrow 2,4$
(b) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 3,4 ; \mathrm{R} \rightarrow 4,5 ; \mathrm{S} \rightarrow 3$
(c) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 3,4 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 2,4$
(d) $\mathrm{P} \rightarrow 1,5 ; \mathrm{Q} \rightarrow 2,3 ; \mathrm{R} \rightarrow 1,5 ; \mathrm{S} \rightarrow 2,3$
Subjective Questions
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Solution:
- (d)
The correct match is 1 i.e., $\mathrm{I}_{2}, \mathrm{NaOH}$ and 5 i.e., $\mathrm{NaOBr}$ The reactions proceed as
For Q, i.e. $\mathrm{NH}{2} \overbrace{\mathrm{Ph}}^{\mathrm{Ph}} \underset{\mathrm{Me}}{\mathrm{H}} \mathrm{OH}+\mathrm{HNO}{2}$
The correct match is 2 i.e. $\left[\mathrm{Ag}\left(\mathrm{NH}{3}\right){2}\right] \mathrm{OH}$ and 3 i.e., Fehling’s solution.
The reactions proceed as
For $R$, i.e. $\underset{\mathrm{Me}}{\mathrm{HO} \underset{\mathrm{Me}}{>}} \underset{\mathrm{OH}}{\mathrm{Ph}}+\mathrm{H}{2} \mathrm{SO}{4}$
The correct match is 1,5 again. The reaction proceed as
For S, i.e. ${ }{\mathrm{Ph}}^{\mathrm{Br} \underbrace{\mathrm{Ph}}{\mathrm{Me}}}$
The correct match is 2,3 .
The reaction proceed as
Rest procedure is same as seen for $Q$ above i.e., via oxidation.
