Answer: d^2/dx^2(log(logx)) = (1/(logx)*(1/x)) * (-1/(logx)) * (1/x) + 1/(logx) * (-1/(x^2))
Therefore, the second order derivative of log(logx) is [(-1/(logx))^2 * (1/x^2)] + (-1/(logx)) * (1/(x^2)).
विम्ल केवलTranspose नहीं parameters।
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