Semiconductors Question 6
Question 6 - 2024 (29 Jan Shift 2)
The truth table for this given circuit is :
(1)
| $\mathrm{A}$ | $\mathrm{B}$ | $\mathrm{Y}$ |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
(2)
| $\mathrm{A}$ | $\mathrm{B}$ | $\mathrm{Y}$ |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
(3)
| $\mathrm{A}$ | $\mathrm{B}$ | $\mathrm{Y}$ |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 0 |
| 1 | 0 | 0 |
| 1 | 1 | 1 |
(4)
| $\mathrm{A}$ | $\mathrm{B}$ | $\mathrm{Y}$ |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
Show Answer
Answer: (2)
Solution:
$\mathrm{Y}=\mathrm{A} \cdot \mathrm{B}+\overline{\mathrm{A}} \cdot \mathrm{B}$
$=(\mathrm{A}+\overline{\mathrm{A}}) \cdot \mathrm{B}$
$\mathrm{Y}=1 \cdot \mathrm{B}$
$\mathrm{Y}=\mathrm{B}$
