Nuclear Physics Question 1
Question 1 - 2024 (01 Feb Shift 1)
The radius of a nucleus of mass number 64 is 4.8 fermi. Then the mass number of another nucleus having radius of 4 fermi is $\frac{1000}{x}$, where $\mathrm{x}$ is
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Answer: (27)
Solution:
$\mathrm{R}=\mathrm{R}_{0} \mathrm{~A}^{1 / 3}$
$R^{3} \propto A$
$\left(\frac{4.8}{4}\right)^{3}=\frac{64}{A}$
$\frac{64}{A}=1.44 \times 1.2$
$A=\frac{64}{1.44 \times 1.2}=\frac{1000}{x}$
$x=\frac{144 \times 12}{64}=27$
