Laws Of Motion Question 15
Question 15 - 2024 (31 Jan Shift 2)
A light string passing over a smooth light fixed pulley connects two blocks of masses $m_{1}$ and $m_{2}$. If the acceleration of the system is $g / 8$, then the ratio of masses is
(1) $\frac{9}{7}$
(2) $\frac{8}{1}$
(3) $\frac{4}{3}$
(4) $\frac{5}{3}$
Show Answer
Answer: (1)
Solution:
$a=\frac{\left(m_{1}-m_{2}\right) g}{\left(m_{1}+m_{2}\right)}=\frac{g}{8}$
$8 \mathrm{~m}{1}-8 \mathrm{~m}{2}=\mathrm{m}{1}+\mathrm{m}{2}$
$7 \mathrm{~m}{1}=9 \mathrm{~m}{2}$
$\frac{\mathrm{m}{1}}{\mathrm{~m}{2}}=\frac{9}{7}$
