Electromagnetic Induction Question 6
Question 6 - 2024 (29 Jan Shift 2)
A horizontal straight wire $5 \mathrm{~m}$ long extending from east to west falling freely at right angle to horizontal component of earth’s magnetic field $0.60 \times 10^{-4} \mathrm{Wbm}^{-2}$. The instantaneous value of emf induced in the wire when its velocity is $10 \mathrm{~ms}^{-1}$ is $\times 10^{-3} \mathrm{~V}$
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Answer: (3)
Solution:
$\mathrm{B}_{\mathrm{H}}=0.60 \times 10^{-4} \mathrm{~Wb} / \mathrm{m}^{2}$
Induced emf e $=\mathrm{B}_{\mathrm{H}} \ell$
$=0.60 \times 10^{-4} \times 10 \times 5$
$=3 \times 10^{-3} \mathrm{~V}$
