Electromagnetic Induction Question 3
Question 3 - 2024 (27 Jan Shift 1)
A rectangular loop of length $2.5 \mathrm{~m}$ and width $2 \mathrm{~m}$ is placed at $60^{\circ}$ to a magnetic field of $4 \mathrm{~T}$. The loop is removed from the field in $10 \mathrm{sec}$. The average emf induced in the loop during this time is
(1) $-2 \mathrm{~V}$
(2) $+2 \mathrm{~V}$
(3) $+1 \mathrm{~V}$
(4) $-1 \mathrm{~V}$
Show Answer
Answer: (3)
Solution:
$$ \begin{aligned} & \text { Average emf }=\frac{\text { Change in flux }}{\text { Time }}=-\frac{\Delta \phi}{\Delta t} \ & =-\frac{0-\left(4 \times(2.5 \times 2) \cos 60^{\circ}\right)}{10} \ & =+1 \mathrm{~V} \end{aligned} $$
