Probability Question 11
Question 11 - 2024 (31 Jan Shift 2)
A coin is based so that a head is twice as likely to occur as a tail. If the coin is tossed 3 times, then the probability of getting two tails and one head is-
(1) $\frac{2}{9}$
(2) $\frac{1}{9}$
(3) $\frac{2}{27}$
(4) $\frac{1}{27}$
Show Answer
Answer (1)
Solution
Let probability of tail is $\frac{1}{3}$
$\Rightarrow$ Probability of getting head $=\frac{2}{3}$
$\therefore$ Probability of getting 2 tails and 1 head
$=\left(\frac{1}{3} \times \frac{2}{3} \times \frac{1}{3}\right) \times 3$
$=\frac{2}{27} \times 3$
$=\frac{2}{9}$
