Permutation Combination Question 8
Question 8 - 2024 (31 Jan Shift 2)
The number of ways in which 21 identical apples can be distributed among three children such that each child gets at least 2 apples, is
(1) 406
(2) 130
(3) 142
(4) 136
Show Answer
Answer (4)
Solution
After giving 2 apples to each child 15 apples left now 15 apples can be distributed in ${ }^{15+3-1} \mathrm{C}{2}={ }^{17} \mathrm{C}{2}$ ways $=\frac{17 \times 16}{2}=136$
