The area (in square units) of the region bounded by the parabola $\mathrm{y}^{2}=4(\mathrm{x}-2)$ and the line $\mathrm{y}=2 \mathrm{x}-8$
(1) 8
(2) 9
(3) 6
(4) 7
Let $X=x-2$
$y^{2}=4 x, \quad y=2(x+2)-8$
$y^{2}=4 x, \ldots y=2 x-4$
$A=\int_{-2}^{4} \frac{y^{2}}{4}-\frac{y+4}{2}$
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