Structure Of Atom Question 13
Question 13 - 2024 (31 Jan Shift 2)
The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are
(1) $\mathrm{n}=4, l=2, \mathrm{~m}=-1, s=+\frac{1}{2}$
(2) $\mathrm{n}=4, l=0, \mathrm{~m}=0, s=+\frac{1}{2}$
(3) $\mathrm{n}=3, l=0, \mathrm{~m}=1, s=+\frac{1}{2}$
(4) $\mathrm{n}=2, l=0, \mathrm{~m}=0, s=+\frac{1}{2}$
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Answer (2)
Solution
${ }_{19} \mathrm{~K} 1 \mathrm{~s}^{2}, 2 \mathrm{~s}^{2}, 2 \mathrm{p}^{6}, 3 \mathrm{~s}^{2}, 3 \mathrm{p}^{6}, 4 \mathrm{~s}^{1}$.
Outermost orbital of potassium is $4 \mathrm{~s}$ orbital
$\mathrm{n}=4,1=0, \mathrm{~m}_{1}=0, \mathrm{~s}= \pm \frac{1}{2}$.
