Solutions Question 5
Question 5 - 2024 (29 Jan Shift 1)
A solution of $\mathrm{H}{2} \mathrm{SO}{4}$ is $31.4 % \mathrm{H}{2} \mathrm{SO}{4}$ by mass and has a density of $1.25 \mathrm{~g} / \mathrm{mL}$. The molarity of the $\mathrm{H}{2} \mathrm{SO}{4}$ solution is ________ $\mathrm{M}$ (nearest integer)
[Given molar mass of $\mathrm{H}{2} \mathrm{SO}{4}=98 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
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Answer (4)
Solution
$M=\frac{n_{\text {solute }}}{V} \times 1000$
$=\frac{\left(\frac{31.4}{98}\right)}{\left(\frac{100}{1.25}\right)} \times 1000$
$=4.005 \approx 4$
