Aldehydes And Ketones Question 1
Question 1 - 2024 (01 Feb Shift 1)
Match List - I with List -II.
| List - I (Reactions) | List - II (Reagents) | ||
|---|---|---|---|
| (A) | $\mathrm{CH}{5}\left(\mathrm{CH}{2}\right){5}-\|{\mathrm{O}}^{\mathrm{C}}-\mathrm{OC}{2} \mathrm{H}{5} \rightarrow \mathrm{CH}{3}\left(\mathrm{CH}{2}\right)_{3} \mathrm{CHO}$ | (I) | $\mathrm{CH}{3} \mathrm{MgBr}, \mathrm{H}{2} \mathrm{O}$ |
| (B) | $\mathrm{C}{6} \mathrm{H}{5} \mathrm{COC}{6} \mathrm{H}{5} \rightarrow \mathrm{C}{6} \mathrm{H}{5} \mathrm{CH}{2} \mathrm{C}{6} \mathrm{H}_{5}$ | (II) | $\mathrm{Zn}(\mathrm{Hg})$ and conc. $\mathrm{HCl}$ |
| (C) | $\mathrm{C}{6} \mathrm{H}{5} \mathrm{CHO} \rightarrow \mathrm{C}{6} \mathrm{H}{5} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}$ | (III) | $\mathrm{NaBH}_{4}, \mathrm{H}^{+}$ |
| (D) |  |
(IV) | DIBAL- $\mathrm{H}, \mathrm{H}_{2} \mathrm{O}$ |
Choose the correct answer from options given below:
(1) A-(III), (B)-(IV), (C)-(I), (D)-(II)
(2) A-(IV), (B)-(II), (C)-(I), (D)-(III)
(3) A-(IV), (B)-(II), (C)-(III), (D)-(I)
(4) A-(III), (B)-(IV), (C)-(II), (D)-(I)
Show Answer
Answer (2)
Solution
Formula: Reduction, DIABAL-H reduction
$\mathrm{CH}{3}\left(\mathrm{CH}{2}\right){5} \mathrm{COOC}{2} \mathrm{H}{5} \xrightarrow{\text { DIBAL-H, } \mathrm{H}{2} \mathrm{O}} \mathrm{CH}{3}\left(\mathrm{CH}{2}\right)_{5} \mathrm{CHO}$
$\mathrm{C}{6} \mathrm{H}{5} \mathrm{COC}{6} \mathrm{H}{5} \xrightarrow{\mathrm{Zn}(\mathrm{Hg}) \backslash & \text { conc. } \mathrm{HCl}} \mathrm{C}{6} \mathrm{H}{5} \mathrm{CH}{2} \mathrm{C}{6} \mathrm{H}_{5}$
$\mathrm{C}{6} \mathrm{H}{5} \mathrm{CHO} \xrightarrow[\mathrm{H}{2} \mathrm{O}]{\mathrm{CH}{3} \mathrm{MgBr}} \mathrm{C}{6} \mathrm{H}{5} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}$
$\mathrm{CH}{3} \mathrm{COCH}{2} \mathrm{COOC}{2} \mathrm{H}{5} \xrightarrow{\mathrm{NaBH}{4}, \mathrm{H}^{+}} \mathrm{CH}{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}{2} \mathrm{COOC}{2} \mathrm{H}_{5}$
