Wave Optics Question 7
Question 7 - 30 January - Shift 2
In a Young’s double slit experiment, the intensities at two points, for the path difference $\frac{\lambda}{4}$ and $\frac{\lambda}{3}$ ( $\lambda$ being the wavelength of light used) are $I_1$ and $I_2$ respectively. If $I_0$ denotes the intensity produced by each one of the individual slits, then $\frac{I_1+I_2}{I_0}=$
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Answer: (3)
Solution:
Formula: YDSE
$ \begin{aligned} & I=4 I_0 \cos ^{2}(\frac{\Delta \phi}{2}) \\ & I_1=4 I_0 \cos ^{2}(\frac{\pi}{4})=2 I_0 \\ & I_2=4 I_0 \cos ^{2}(\frac{2 \pi}{3})=I_0 \\ & \Rightarrow \frac{I_1+I_2}{I_0}=3 \end{aligned} $
