Thermodynamics Question 8
Question 8 - 25 January - Shift 2
The graph between two temperature scales P and Q is shown in the figure. Between upper fixed point and lower fixed point there are 150 equal divisions of scale P and 100 divisions on scale Q. The relationship for conversion between the two scales is given by :
(1) $\frac{t_Q}{150}=\frac{t_P-180}{100}$
(2) $\frac{t_Q}{100}=\frac{t_P-30}{150}$
(3) $\frac{t_P}{180}=\frac{t_Q-40}{100}$
(4) $\frac{t_P}{100}=\frac{t_Q-180}{150}$
Show Answer
Answer: (2)
Solution:
Formula: Liquid Thermometer
$\frac{\text { reading on scale-Lower fixed point }}{\text { upper fixed point-lower fixed point }}=$ constant
$\frac{t_P-30}{180-30}=\frac{t_Q-0}{100-0}$
$\frac{t_p-30}{150}=\frac{t_Q}{100}$
