Oscillations Question 8
Question 8 - 30 January - Shift 2
The velocity of a particle executing SHM varies with displacement ( $x)$ as $4 v^{2}=50-x^{2}$. The time period of oscillations is $\frac{x}{7} s$. The value of $x$ is ……… $(.$ Take $.\pi=\frac{22}{7})$
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Answer: (88)
Solution:
Formula: Time period of Simple harmonic motion
$4 v^{2}=50-x^{2}$
$\Rightarrow v=\frac{1}{2} \sqrt{50-x^{2}}$
$\omega=\frac{1}{2}$
$T=\frac{2 \pi}{\omega}=4 \pi=\frac{88}{7}$
