Oscillations Question 7
Question 7 - 30 January - Shift 2
For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1 kg$, the angular frequency is $\omega_1$. When the mass block is $2 kg$ the angular frequency is $\omega_2$. The ratio $\omega_2 / \omega_1$ is :
(1) $\sqrt{2}$
(2) $\frac{1}{\sqrt{2}}$
(3) 2
(4) $\frac{1}{2}$
Show Answer
Answer: (2)
Solution:
Formula: Angular frequency of Simple harmonic motion
$\omega=\sqrt{\frac{k}{m}}$
$\frac{\omega_2}{\omega_1}=\sqrt{\frac{m_1}{m_2}}=\sqrt{\frac{1}{2}}$
