Oscillations Question 5
Question 5 - 29 January - Shift 2
A particle of mass $250 g$ executes a simple harmonic motion under a periodic force $F=(-25$ x) N. The particle attains a maximum speed of $4 m / s$ during its oscillation. The amplitude of the motion is $cm$.
Show Answer
Answer: (40)
Solution:
Formula: Simple harmonic motion
$\frac{1}{4} a=-25 x \quad ; \quad a=-100 x$
$ \omega^{2}=100 \quad \omega=10 $
$\omega A=4$
$A=\frac{4}{10}=0.4 m$
$A=40 cm$
