Oscillations Question 4
Question 4 - 25 January - Shift 2
A particle executes simple harmonic motion between $x=-A$ and $x=+A$. If time taken by particle to go from $x=0$ to $\frac{A}{2}$ is $2 s$; then time taken by particle in going from $x=\frac{A}{2}$ to $A$ is :
(1) $3 s$
(2) $2 s$
(3) $1.5 s$
(4) $4 s$
Show Answer
Answer: (4)
Solution:
Formula: Angular Frequency
Let time from 0 to $A / 2$ is $t_1$
$\&$ from $A / 2$ to $A$ is $t_2$
then $\omega t_1=\pi / 6$
$\omega t_2=\pi / 3$ $\frac{t_1}{t_2}=\frac{1}{2}$ $t_2=2 t_1=2 \times 2=4 sec$
