Nuclear Physics Question 3
Question 3 - 25 January - Shift 1
The ratio of the density of oxygen nucleus $( _8^{16} O)$ and helium nucleus $( _2^{4} He)$ is
(1) $4: 1$
(2) $8: 1$
(3) $1: 1$
(4) $2: 1$
Show Answer
Answer: (3)
Solution:
Formula: Radius Of Nucleus
Nuclear density is independent of mass number
As nuclear density $=\frac{Au}{\frac{4}{3} \pi R^{3}}$
Also, $R=R_0 A^{\frac{1}{3}}$
And $R^{3}=R_0^{3} A$
$\Rightarrow$ Nuclear density $=\frac{Au}{\frac{4}{3} \pi R_0^{3} A}$
Nuclear density $=\frac{3 u}{4 \pi R_0^{3}}$
