Nuclear Physics Question 1
Question 1 - 24 January - Shift 1
Consider the following radioactive decay process $ _84^{218} A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\gamma} A_3 \xrightarrow{\alpha} A_4 \xrightarrow{\beta^{+}} A_5 \xrightarrow{\gamma} A_6$ The mass number and the atomic number $A_6$ are given by :
(1) 210 and 82
(2) 210 and 84
(3) 210 and 80
(4) 211 and 80
Show Answer
Answer: (3)
Solution:
Formula: Alpha - Decay Process
$ _84^{218} A \xrightarrow{\alpha} _82^{214} A_1 \xrightarrow{\beta^{-}} _83^{214} A_2 \xrightarrow{\gamma} _83^{214} A_3$
$ _83^{214} A_3 \xrightarrow{\alpha} _81^{210} A_4 \xrightarrow{\beta^{+}} _80^{210} A_5 \xrightarrow{\gamma} _80^{210} A_6$
