Motion In Two Dimensions Question 3
Question 3 - 29 January - Shift 1
A stone is projected at angle $30^{\circ}$ to the horizontal. The ratio of kinetic energy of the stone at point of projection to its kinetic energy at the highest point of flight will be :
(1) $1: 2$
(2) $1: 4$
(3) $4: 1$
(4) $4: 3$
Show Answer
Answer: (4)
Solution:
Formula: Kinetic energy
$ \frac{KE _{POP}}{KE _{\text{top }}}=\frac{\frac{1}{2} M(u)^{2}}{\frac{1}{2} M(u \cos 30^{\circ})^{2}}=\frac{4}{3} $
