Mechanical Properties Of Solids Question 1
Question 1 - 24 January - Shift 1
A $100 m$ long wire having cross-sectional area 6.25 $\times 10^{-4} m^{2}$ and Young’s modulus is $10^{10} Nm^{-2}$ is subjected to a load of $250 N$, then the elongation in the wire will be :
(1) $6.25 \times 10^{-3} m$
(2) $4 \times 10^{-4} m$
(3) $6.25 \times 10^{-6} m$
(4) $4 \times 10^{-3} m$
Show Answer
Answer: (4)
Solution:
Formula: Young’s modulus
Elongation in wire $\delta=\frac{F \ell}{AY}$
$\delta=\frac{250 \times 100}{6.25 \times 10^{-4} \times 10^{10}}$
$\delta=4 \times 10^{-3} m$
