Magnetic Effects Of Current Question 5

Question 5 - 25 January - Shift 1

Math List I with List II

List - I
(Current configuration)
List - II
(Magnetic field at
point $O)$
A I. $B_0=\frac{\mu_0 I}{4 \pi r}[\pi+2]$
B II. $B_0=\frac{\mu_0}{4} \frac{I}{r}$
$C$ III
.
$B_0=\frac{\mu_0 I}{2 \pi r}[\pi-1]$
D $\sqrt{\underset{I}{\text{ mathon }}}$ IV $B_0=\frac{\mu_0 I}{4 \pi r}[\pi+1]$

Choose the correct answer from the option given below:

(1) A-III, B-IV, C-I, D-II

(2) A-I, B-III, C-IV, D-II

(3) A-III, B-I, C-IV, D-II

(4) A-II, B-I, C-IV, D-III

Show Answer

Answer: (3)

Solution:

Formula: Magnetic field due to circular loop, Magnetic field due to Infinite long wire

Math List I with List II

List - I
(Current configuration)
List - II
(Magnetic field at
point O)
$A$ $I$. $B_{0}=\frac{\mu_{0} I}{4 \pi r}[\pi+2]$
$B$ $II$. $~B_{0}=\frac{\mu_{0}}{4} \frac{I}{r}$
$C$ $I$ $III$ $B_{0}=\frac{\mu_{0} I}{2 \pi r}[\pi-1]$
$D$ $I$ $I$ $I$

Choose the correct answer from the option given below:

(1) A-III, B-IV, C-I, D-II

(2) A-I, B-III, C-IV, D-II

(3) A-III, B-I, C-IV, D-II

(4) A-II, B-I, C-IV, D-III