Laws Of Motion Question 8
Question 8 - 30 January - Shift 2
A block of $\sqrt{3} kg$ is attached to a string whose other end is attached to the wall. An unknown force $F$ is applied so that the string makes an angle of $30^{\circ}$ with the wall. The tension $T$ is :
(Given $g=10 ms^{-2}$ )
(1) $20 N$
(2) $25 N$
(3) $10 N$
(4) $15 N$
Show Answer
Answer: (1)
Solution:
Formula: Second Law Of Motion
$\theta=30^{\circ}$
$\cos \theta=\frac{\sqrt{3} g}{T}$
$\Rightarrow \frac{\sqrt{3}}{2}=\frac{\sqrt{3} g}{T}$
$\Rightarrow T=20 N$
