Laws Of Motion Question 5
Question 5 - 29 January - Shift 2
Force acts for $20 s$ on a body of mass $20 kg$,starting from rest, after which the force ceases and then body describes $50 m$ in the next $10 s$. The value of force will be :
(1) $40 N$
(2) $5 N$
(3) $20 N$
(4) $10 N$
Show Answer
Answer: (2)
Solution:
Formula: Second Law Of Motion
$50=V \times 10$
$V=5 m / s$
$V=0+a \times 20$
$5=a \times 20$
$a=\frac{1}{4} m / s^{2}$
$F=ma=20 \times \frac{1}{4}=5 N$
