Laws Of Motion Question 12

Question 12 - 31 January - Shift 2

A stone of mass $1 kg$ is tied to end of a massless string of length $1 m$. If the breaking tension of the string is $400 N$, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is:

(1) $20 ms^{-1}$

(2) $40 ms^{-1}$

(3) $400 ms^{-1}$

(4) $10 ms^{-1}$

Show Answer

Answer: (1)

Formula: Centripetal Force