Gravitation Question 9
Question 9 - 29 January - Shift 1
Two particles of equal mass ’ $m$ ’ move in a circle of radius ’ $r$ ’ under the action of their mutual
gravitational attraction. The speed of each particle will be :
(1) $\sqrt{\frac{GM}{2 r}}$
(2) $\sqrt{\frac{4 GM}{r}}$
(3) $\sqrt{\frac{GM}{r}}$
(4) $\sqrt{\frac{GM}{4 r}}$
Show Answer
Answer: (4)
Solution:
Formula: Universal Law of Gravitation, Centripetal Force
$\frac{G m^{2}}{4 r^{2}}=\frac{m v^{2}}{r}$
