Electrostatics Question 20
Question 20 - 01 February - Shift 1
Two equal positive point charges are separated by a distance $2 a$. The distance of a point from the centre of the line joining two charges on the equatorial line (perpendicular bisector) at which force experienced by a test charge $q_0$ becomes maximum is $\frac{a}{\sqrt{x}}$. The value of $x$ is
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Answer: (2)
Solution:
$F=\frac{2 K q q_0 x}{(x^{2}+a^{2})^{3 / 2}}$
For $F$ to be maximum
$ x=\frac{\frac{d}{d} x}{\sqrt{2}}=0 $
