Electrostatics Question 11
Question 11 - 29 January - Shift 2
For a charged spherical ball, electrostatic potential inside the ball varies with $r$ as $V=2 ar^{2}+b$.
Here, $a$ and $b$ are constant and $r$ is the distance from the center. The volume charge density inside the ball is $-\lambda a \varepsilon$. The value of $\lambda$ is
$\varepsilon=$ permittivity of medium.
Show Answer
Answer: (12)
Solution:
Formula: Electric Potential
$E=-\frac{dV}{dr}=-4 ar \equiv \frac{\rho r}{3 \varepsilon_0}$ (compare)
Result inside uniformly charged solid sphere
$\rho=-12 a \varepsilon_0$
$\lambda=12$
