Dual Nature Of Matter Question 6
Question 6 - 29 January - Shift 2
The ratio of de-Broglie wavelength of an $\alpha$-particle and a proton accelerated from rest by the same potential is $\frac{1}{\sqrt{m}}$, the value of $m$ is
(1) 4
(2) 16
(3) 8
(4) 2
Show Answer
Answer: (3)
Solution:
Formula: De Broglie wavelength
$ \begin{aligned} & \frac{\lambda _{\alpha}}{\lambda_p}=\frac{h}{\frac{\sqrt{2 m _{\alpha} q _{\alpha} V}}{h}} \\ & \frac{\lambda _{\alpha}}{\lambda_p}=\sqrt{\frac{1}{8} \quad m}=8 \end{aligned} $
Ans. 3
