Dual Nature Of Matter Question 12
Question 12 - 01 February - Shift 1
A proton moving with one tenth of velocity of light has a certain de Broglie wavelength of $\lambda$. An alpha particle having certain kinetic energy has the same de-Brogle wavelength $\lambda$. The ratio of kinetic energy of proton and that of alpha particle is:
(1) $2: 1$
(2) $4: 1$
(3) $1: 2$
(4) $1: 4$
Show Answer
Answer: (2)
Solution:
Formula: Photoelectric Effect
$K E=\frac{p^{2}}{2 m}=\frac{h^{2}}{2 m \lambda^{2}}$
$\frac{K E_p}{K E _{\alpha}}=\frac{m _{\alpha}}{m_p}=4: 1$
