Current Electricity Question 12
Question 12 - 30 January - Shift 1
In the following circuit, the magnitude of current $I_1$, is A.
Show Answer
Answer: (1)
Solution:
Formula: Kirchhoff’s Laws
Junction law at $A$,
$\frac{x-(y+5)}{1}+\frac{x-2}{2}+\frac{x-0}{2}=0$
Junction law at B,
$\frac{y+5-x}{1}+\frac{y-0}{1}+\frac{y-2}{1}=0$
On solving equation (1) and Equation (2)
$x=3$
and $ y=0$
At $D$ junction
$I_1=i_1+i_2$
$I_1=\frac{y-0}{1}+\frac{x-0}{2}$
$=\frac{0-0}{1}+\frac{3-0}{2}$
