Communication System Question 5
Question 5 - 29 January - Shift 2
The modulation index for an A.M. wave having maximum and minimum peak to peak voltages of $14 mV$ and $6 mV$ respectively is :
(1) 1.4
(2) 0.4
(3) 0.2
(4) 0.6
Show Answer
Answer: (2)
Solution:
Formula: Modulation Index
$\mu=$ modulation index $=\frac{A _{\text{max }}-A _{\text{min }}}{A _{\text{max }}+A _{\text{min }}}$
$=\frac{14-6}{14+6}=0.4$
