Alternating Current Question 1
Question 1 - 24 January - Shift 1
In the circuit shown in the figure, the ratio of the quality factor and the band width is s.
Show Answer
Answer: (10)
Solution:
Formula: AC and DC Current
$ \begin{aligned} & \Delta \omega=\frac{R}{L} \\ & Q=\frac{\omega_0}{\Delta \omega}=\omega_0 \frac{L}{R} \\ & \omega_0=\frac{1}{\sqrt{3 \times 27 \times 10^{-6}}}=\frac{1}{9 \times 10^{-3}} \\ & \frac{Q}{\Delta \omega}=\frac{\omega_0 \frac{L}{R}}{\frac{R}{L}}=\omega_0 \frac{L^{2}}{R^{2}}=\sqrt{\frac{1}{LC} \frac{L^{2}}{R^{2}}} \\ & =\frac{1}{9 \times 10^{-3}} \times \frac{9}{100}=10 s \end{aligned} $
