Three Dimensional Geometry Question 35
Question 35 - 01 February - Shift 2
Let $\alpha x+\beta y+y z=1$ be the equation of a plane passing through the point $(3,-2,5)$ and perpendicular to the line joining the points $(1,2,3)$ and $(-2,3,5)$. Then the value of $\alpha \beta y$ is equal to _________
Show Answer
Answer: 6
Solution:
Formula: Equation Of A Plane
Normal vector of plane = (3\hat i - \hat j - 2\hat k)
Plane : 3x – y – 2z + λ = 0
Point (3, –2, 5) satisfies the plan
λ = –1
3x – y – 2z = 1
αβy = 6
