Mathematical Reasoning Question 11
Question 11 - 01 February - Shift 1
The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to
(1) $(\sim p) \wedge(\sim q)$
(2) $p \wedge(\sim q)$
(3) $(\sim p) \vee(\sim q)$
(4) $(\sim p) \vee q$
Show Answer
Answer: (1)
Solution:
$\sim(q \vee((\sim q) \wedge p))$
$=\sim q \wedge \sim((\sim q) \wedge p)$
$=\sim q \wedge(q \vee \sim p)$
$=(\sim q \wedge q) \vee(\sim q \wedge \sim p)$
$=(\sim q \wedge \sim p)$