Structure Of Atom Question 8
Question 8 - 30 January - Shift 1
The energy of one mole of photons of radiation of frequency $2 \times 10^{12} Hz$ in $J mol^{-1}$ is
(Nearest integer)
(Given: $h=6.626 \times 10^{-34} Js$
$N_A=6.022 \times 10^{23} mol^{-1}$ )
Show Answer
Answer: (798)
Solution:
Formula: Planck’s Quantum Theory
For one photon $E=hv$
For one mole photon,
$ \begin{aligned} E & =6 \cdot 023 \times 10^{23} \times 6 \cdot 626 \times 10^{-34} \times 2 \times 10^{12} \\ & =798 \cdot 16 J \\ & \approx 798 J \end{aligned} $
