Structure Of Atom Question 12
Question 12 - 31 January - Shift 2
Arrange the following orbitals in decreasing order of energy?
(A) $n=3,1=0, m=0$
(B) $n=4,1=0, m=0$
(C) $n=3,1=1, m=0$
(D) $n=3,1=2, m=1$
The correct option for the order is :
(1) B $>$ D $>$ C $>$ A
(2) D $>$ B $>$ C $>$ A
(3) A $>$ C $>$ B $>$ D
(4) D $>$ B $>$ A $>$ C
Show Answer
Answer: (2)
Solution:
Formula: Quantum Theory
(A) $n=3 ; 1=0 ; m=0 ; 3$ s orbital
(B) $n=4 ; 1=0 ; m=0 ; 4 s$ orbital
(C) $n=3 ; 1=1 ; m=0 ; 3 p$ orbital
(D) $n=3 ; 1=2 ; m=0 ; 3 d$ orbital
As per Hund’s rule energy is given by $(n+l$ ) value.
If value of $(n+l)$ remains same then energy is given by $n$ only.
