The spin only magnetic moment of $[Mn(H_2 O)_6]^{2-}$ complexes is B.M. (Nearest integer)
(Given : Atomic no. of $Mn$ is 25)
$([Mn(H_2 O)_6]^{2+}.$
$Mn^{2+}=3 d^{5}$
$\mu=\sqrt{5(5+2)}=5.91 BM$
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