Chemical Equilibrium Question 1
Question 1 - 24 January - Shift 1
For independent process at $300 K$.
| Process | $\Delta \mathbf{H} / \mathbf{k J ~ m o l}^{\mathbf{- 1}}$ | $\Delta \mathbf{S} / \mathbf{J}^{-\mathbf{1}}$ |
|---|---|---|
| A | -25 | 40 |
| B | -22 | -50 |
| C | 25 | 20 |
| D | 22 | mothon |
The number of non-spontaneous process from the following is
Show Answer
Answer: (2)
Solution:
Formula: Criteria of spontaneity
$\Delta G=\Delta H-T \Delta S$
A : $\Delta G(J mol^{-1})=-25 \times 10^{3}+80 \times 300:-ve$
B : $\Delta G(J mol^{-1})=-22 \times 10^{3}-40 \times 300:-ve$
$C: \Delta G(J mol^{-1})=25 \times 10^{3}+300 \times 50:+ve$
$D: \Delta G(J mol^{-1})=22 \times 10^{3}-20 \times 300:+ve$
Processes C and D are non-spontaneous.
