Chemical Bonding And Molecular Structure Question 8
Question 8 - 30 January - Shift 2
Match List I with List II:
| List I (Complexes) |
List II (Hybridis ation) |
||
|---|---|---|---|
| (A) | $[Ni(CO)_4]$ | I | $sp^{3}$ |
| (B) | $[Cu(NH_3)_4]^{2+}$ | II | $dsp^{2}$ |
| (C) | $[Fe(NH_3)_6]^{2+}$ | III | $sp^{3} d^{2}$ |
| (D) | $[Fe(H_2 O)_6]^{2+}$ | IV | $d^{2} sp^{3}$ |
(1) A - II, B - I, C - III, D - IV
(2) A - I, B - II, C - III, D - IV
(3) A - II, B - I, C - IV, D - III
(4) A - I, B- II, C - IV, D - III
Show Answer
Answer: (4)
Solution:
Formula: VBT
For $[Fe(NH_3)_6]^{+2}, \Delta_0<P$, hence the pairing of electrons does not occur in $t _{2 g}$. Therefore complex is outer orbital and its hybridisation is $sp^{3} d^{2}$.
| List I (Complexes) |
List II (Hybridisation) |
|---|---|
| $[Ni(CO)_4]$ | $sp^{3}$ |
| $[Cu(NH_3)_4]^{2+}$ | $dsp^{2}$ |
| $[Fe(NH_3)_6]^{2+}$ | $sp^{3} d^{2}$ |
| $[Fe(H_2 O)_6]^{2+}$ | $sp^{3} d^{2}$ |
