Biomolecules Question 9
Question 9 - 31 January - Shift 2
Compound $A, C_5 H _{10} O_5$, given a tetraacetate with $Ac_2 O$ and oxidation of $A$ with $Br_2-H_2 O$ gives an acid, $C_5 H _{10} O_6$. Reduction of $A$ with $HI$ gives isopentane. The possible structure of $A$ is :
(1)
(2)
(3)
(4) $CHO$
Show Answer
Answer: (1)
Solution:
Formula: Oxidation
(i) Formation of tetraacetete with $Ac_2 O$ means compound $A$ has four - $OH$ linkage.
Reduction of A with HI gives Isopentane i.e. molecule contains five carbon atom.
