JEE Main 12 Jan 2019 Morning Question 25

Question: An ideal gas occupies a volume of $ 2m^{3} $ at a pressure of $ 3\times 10^{6}Pa $ . The energy of the gas is [JEE Main Online Paper Held On 12-Jan-2019 Morning]

Options:

A) $ 9\times 10^{6}J $

B) $ 3\times 10^{2}J $

C) $ 6\times 10^{4}J $

D) $ 10^{8}J $

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Answer:

Correct Answer: A

Solution:

  • We know that $ PV=\frac{2}{3}E $ $ E=\frac{3PV}{2}=3\times \frac{3\times 10^{6}}{2}\times 2=9\times 10^{6}J $