JEE Main 12 Jan 2019 Evening Question 6
Question: A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0 m $ {s^{-1}} $ , at right angles to the horizontal component of the earths magnetic field of $ 0.3\times {10^{-4}}Wb/m^{2}. $ The value of the induced emf in wire is
[JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ 0.3\times {10^{-3}}V $
B) $ 2.5\times {10^{-3}}V $
C) $ 1.5\times {10^{-3}}V $
D) $ 1.1\times {10^{-3}}V $
Show Answer
Answer:
Correct Answer: C
Solution:
- The motional emf is given as $ \varepsilon =| v(\overrightarrow{{}l}\times \overrightarrow{{}B}) |= $ $ 5\times (0.3\times {10^{-4}})(10)sin90^{o}=1.5\times {10^{-3}}V $
