JEE Main 12 Jan 2019 Evening Question 21
Question: In the given circuit diagram, the currents, $ I _1=0.3A,I _4=0.8A $ and $ I _5=0.4A, $ are flowing as shown. The currents $ I _2,I _3 $ and $ I _6, $ respectively, are
[JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ 1.1A,0.4A,0.4A $
B) $ -0.4A,0.4A,1.1A $
C) $ 1.1A,-0.4A,0.4A $
D) $ 0.4A,1.1A,0.4A $
Show Answer
Answer:
Correct Answer: A
Solution:
- Applying KCL at junction $ P _1,I _5=I _6\Rightarrow I _6=0.4A $
From KCL at point $ R,I _1+I _2=I _4 $
$ \Rightarrow $ $ I _2=I _4-I _1=0.8-(-0.3)=1.1A $
At point $ S,I _5+I _3=I _4\Rightarrow I _3=I _4-I _5 $
$ \Rightarrow I _3=0.8-0.4=0.4A. $
