JEE Main 12 Jan 2019 Evening Question 9
Question: If a straight line passing through the point $ P( -3,4 ) $ is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is
[JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ 4x+3y=0 $
B) $ 4x-3y+24=0 $
C) $ 3x-4y+25=0 $
D) $ x-y+7=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
- Let the equation of the line is $ \frac{x}{a}+\frac{y}{b}=1 $
$ \therefore $ $ \frac{a}{2}=-3 $ and $ \frac{b}{2}=4 $
$ \Rightarrow $ $ a=-6 $ and $ b=8 $ So, equation of the line is $ \frac{x}{-6}+\frac{y}{8}=1 $
$ \Rightarrow $ $ 4x-3y+24=0 $
