JEE Main 12 Jan 2019 Evening Question 5
Question: The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 B.M. The suitable ligand for this complex is
[JEE Main Online Paper Held On 12-Jan-2019 Evening]
Options:
A) $ NC{S^{-}} $
B) $ C{N^{-}} $
C) CO
D) ethylenediamine
Show Answer
Answer:
Correct Answer: A
Solution:
- $ \mu =\sqrt{n(n+2)}=5.9B.M. $
$ \Rightarrow n=5 $ (Where, n = no. of unpaired electrons]
$ M{n^{2+}}=[Ar]3d^{5} $
Five unpaired electrons in 3d-orbital are possible under influence of only weak field ligand. Among the given, $ NC{S^{-}} $ is relatively weak.
